An easy to use, free and quick solution finder is every math student’s dream. You get the correct answers. However this doesn’t help much in a test where these online tools are not at your disposal. So what if there was an online math algebra solver who would help you find the right answers and figure out how you got there, in your way and at your pace? This is exactly the type of service that online tutors provide with online algebra solvers who are knowledgeable and provide customized service based on your abilities and aptitude.

Algebra solvers from online tutoring sites like www.tutorvista.com, www.smarthinking.com, www.tutornext.com, to name a few, provide easily accessible algebra help while helping you get a hang of those concepts which seem to baffle.

Algebra solvers from online tutoring sites like www.tutorvista.com, www.smarthinking.com, www.tutornext.com, to name a few, provide easily accessible algebra help while helping you get a hang of those concepts which seem to baffle.

## Algebra Problem Solver

### Solved Example

**Question:**If x = 2, find 4x + 10.

**Solution:**

4x + 10 = 4 * 2 + 10

= 8 + 10

= 18

= 8 + 10

= 18

## Free Algebra Solver

## Algebra 1 Solver

### Solved Example

**Question:**The sum of two consecutive numbers is 25. What are the numbers?

**Solution:**

Firstly, translate verbal language into algebraic language.

Let first number = x

Then the second number = x + 1.

The problem states:

Sum of two consecutive numbers = 25

=> x + (x + 1) = 25

=> x + x + 1 = 25

=> 2x + 1 = 25

Subtract 1 from both sides of the equation,

=> 2x + 1 - 1 = 25 - 1

=> 2x = 24

Divide from both sides by 2,

=> $\frac{2x}{2} = \frac{24}{2}$

=> x = 12

=> First number = $12$,

Second number = x + 1 = 12 + 1 = $13$

Let first number = x

Then the second number = x + 1.

The problem states:

Sum of two consecutive numbers = 25

=> x + (x + 1) = 25

=> x + x + 1 = 25

=> 2x + 1 = 25

Subtract 1 from both sides of the equation,

=> 2x + 1 - 1 = 25 - 1

=> 2x = 24

Divide from both sides by 2,

=> $\frac{2x}{2} = \frac{24}{2}$

=> x = 12

=> First number = $12$,

Second number = x + 1 = 12 + 1 = $13$

## Algebra 2 Solver

## Algebra Solver Free

## College Algebra Solver

### Solved Example

**Question:**The length of a rectangle exceeds its width by 3 feet. If the area is 10 square feet, find its dimensions.

**Solution:**

Let width of the rectangle = x

then length of the rectangle = x + 3

Since the area of a rectangle is, Area = length * width

=> Area of given rectangle = (x + 3) * x

The problem states:

=> (x + 3)x = 10

=> x * x + 3x = 10

=> x

=> x

=> x(x + 5) - 2(x + 5) = 0

=> (x - 2)(x + 5) = 0

=> x - 2 = 0 or x + 5 = 0

=> x = 2 or x = -5

x = -5 is discarded, because rectangle can not have a negative width.

so x = 2 is the answer.

=> Width of rectangle = $2$

and length = x + 3 = 2 + 3 = $5$.

then length of the rectangle = x + 3

Since the area of a rectangle is, Area = length * width

=> Area of given rectangle = (x + 3) * x

The problem states:

=> (x + 3)x = 10

=> x * x + 3x = 10

=> x

^{2}+ 3x - 10 = 0=> x

^{2}+ 5x - 2x - 10 = 0=> x(x + 5) - 2(x + 5) = 0

=> (x - 2)(x + 5) = 0

=> x - 2 = 0 or x + 5 = 0

=> x = 2 or x = -5

x = -5 is discarded, because rectangle can not have a negative width.

so x = 2 is the answer.

=> Width of rectangle = $2$

and length = x + 3 = 2 + 3 = $5$.

## Algebra Equation Solver

### Solved Example

**Question:**Solve for x, 3x + 6 = x - 2

**Solution:**

Given, 3x + 6 = x - 2

Subtract x from both sides of the equation,

=> 3x - x + 6 = x - x - 2

=> 2x + 6 = - 2

Subtract 6 from both sides of the equation,

=> 2x + 6 - 6 = -2 - 6

=> 2x = - 8

Divide both side by 2,

=> $\frac{2x}{2} = \frac{-8}{2}$

=> $x = - 4$, is the solution.

Check the solution by substituting x = - 4 in the original equation.

Subtract x from both sides of the equation,

=> 3x - x + 6 = x - x - 2

=> 2x + 6 = - 2

Subtract 6 from both sides of the equation,

=> 2x + 6 - 6 = -2 - 6

=> 2x = - 8

Divide both side by 2,

=> $\frac{2x}{2} = \frac{-8}{2}$

=> $x = - 4$, is the solution.

Check the solution by substituting x = - 4 in the original equation.

**Left Side**= 3x + 6 = 3(- 4) + 6 = -12 + 6 = $- 6$**Right Side**= x - 2 = - 4 - 2 = $- 6$## Algebra Expression Solver

## Algebra Word Problem Solver

### Solved Example

**Question:**One number is 5 more than another. The sum of the smaller more than three times the larger, is 39. What are the two numbers?

**Solution:**

Let x be the smaller number

Then the larger number is 5 more = x + 5

The problem states,

x + 3(x + 5) = 39

=> x + 3x + 15 = 39

=> 4x + 15 = 39

Subtract 15 from both sides of the equation,

=> 4x + 15 - 15 = 39 - 15

=> 4x = 24

Divide both side by 4,

=> $\frac{4x}{4} = \frac{24}{4}$

=> x = 6

=> x = $6$ is the smaller number.

So the larger number is x + 5 = 6 + 5 = $11$.

Then the larger number is 5 more = x + 5

The problem states,

x + 3(x + 5) = 39

=> x + 3x + 15 = 39

=> 4x + 15 = 39

Subtract 15 from both sides of the equation,

=> 4x + 15 - 15 = 39 - 15

=> 4x = 24

Divide both side by 4,

=> $\frac{4x}{4} = \frac{24}{4}$

=> x = 6

=> x = $6$ is the smaller number.

So the larger number is x + 5 = 6 + 5 = $11$.