Algebra Solver

An easy to use, free and quick solution finder is every math student’s dream. You get the correct answers. However this doesn’t help much in a test where these online tools are not at your disposal. So what if there was an online math algebra solver who would help you find the right answers and figure out how you got there, in your way and at your pace? This is exactly the type of service that online tutors provide with online algebra solvers who are knowledgeable and provide customized service based on your abilities and aptitude.
Algebra solvers from online tutoring sites like www.tutorvista.com, www.smarthinking.com, www.tutornext.com, to name a few, provide easily accessible algebra help while helping you get a hang of those concepts which seem to baffle.

Algebra Problem Solver

It’s not just enough to get the right answer to a problem. Since the method is just as crucial as the answer, an effective algebra problem solver takes students through the steps of an algebra math problem. Understanding the natural progression of the solution helps you grasp what you need to do to solve a particular problem.

Solved Example

Question: If x = 2, find 4x + 10.
Solution:
4x + 10 = 4 * 2 + 10

= 8 + 10

= 18
 

Free Algebra Solver

Most of the algebra solvers available online compute the answer to a given problem quickly but when it comes to method, they leave you in the dark. The math algebra solver with steps, on tutoring sites, help you out by giving you free step by step solutions. An illustration of how to solve the problem step by step gives you a clear idea of how to go about similar algebra problems.

Algebra 1 Solver

Algebra 1 is the introduction to variables, equations, graphs and geometry. Getting a sound base in algebra 1 is crucial to understanding the more advanced concepts which follow. Free algebra 1 problem solvers help you practice the concepts with numerous sample questions and worksheets. Algebra 1 equation solvers and algebra 1 word problem solvers familiarize you with both types of problems.

Solved Example

Question: The sum of two consecutive numbers is 25. What are the numbers?

Solution:
Firstly, translate verbal language into algebraic language.
 
Let first number = x

Then the second number = x + 1.

The problem states:
Sum of two consecutive numbers = 25

=> x + (x + 1) = 25

=> x + x + 1 = 25

=> 2x + 1 = 25

Subtract 1 from both sides of the equation,

=> 2x + 1 - 1 = 25 - 1

=> 2x = 24

Divide from both sides by 2,

=> $\frac{2x}{2} = \frac{24}{2}$

=> x = 12

=> First number = $12$,

Second number = x + 1 = 12 + 1 = $13$
 

Algebra 2 Solver

Algebra 2 presents more challenges to the mathematically disinclined. Online algebra 2 solvers can help master these new concepts and provide step by step solutions. Algebra 2 homework help is available as and when required. Online math problem solvers for algebra 2 explain new terms and concepts, and help you practice what you learn so that it stays with you.

Algebra Solver Free

Online algebra solvers are convenient and easy to use and are available whenever a student needs help with algebra or math problems. While a lot of free algebra solvers only compute the answer, some sites offer a more comprehensive solution.

College Algebra Solver  

College algebra equation solvers are  a great way to understand the intricacies of college level  algebra. Free online college algebra solvers can go a long way in helping you grasp the subject and  boost your grades. The step by step break down of algebra problems and the practice problems and  worksheets help students learn thoroughly and conveniently. College algebra word problem solvers available online do more than just show you the right equation, it help you to understand how these problems are worded so that you can soon crack them yourself.

Solved Example

Question: The length of a rectangle exceeds its width by 3 feet. If the area is 10 square feet, find its dimensions.

Solution:
Let width of the rectangle = x

then length of the rectangle = x + 3

Since the area of a rectangle is, Area = length * width

=> Area of given rectangle = (x + 3) * x

The problem states:

=> (x + 3)x = 10

=> x * x + 3x = 10

=> x2 + 3x - 10 = 0

=> x2 + 5x - 2x - 10 = 0

=> x(x + 5) - 2(x + 5) = 0

=> (x - 2)(x + 5) = 0

=> x - 2 = 0    or    x + 5 = 0

=> x = 2         or  x = -5

x = -5 is discarded, because rectangle can not have a negative width.

so x = 2 is the answer.

=> Width of rectangle = $2$

and length = x + 3 = 2 + 3 = $5$.

 

Algebra Equation Solver

Whether it's solving equations, balancing equations, or converting word problems to algebra equations, a free algebra equation solver is always handy. Algebra equation solvers online help with algebra 1 and algebra 2. College algebra equation solvers provide similar help, giving the answer after demonstrating a step by step solution.

Solved Example

Question: Solve for x, 3x + 6 = x - 2

Solution:
Given, 3x + 6 = x - 2

Subtract x from both sides of the equation,

=> 3x - x + 6 = x - x - 2

=> 2x + 6 = - 2

Subtract 6 from both sides of the equation,

=> 2x + 6 - 6 = -2 - 6

=> 2x = - 8

Divide both side by 2,

=> $\frac{2x}{2} = \frac{-8}{2}$

=> $x = - 4$, is the solution.

Check the solution by substituting x = - 4 in the original equation.

Left Side = 3x + 6 = 3(- 4) + 6 = -12 + 6 = $- 6$

Right Side = x - 2 = - 4 - 2 = $- 6$

 

Algebra Expression Solver

Algebraic expressions take some getting used to. With the various rules that accompany solving them the best way is to practice practice practice. Online algebra expression solvers teach you the solutions, breaking them down step by step. Most online algebra expression solvers also give you access to plenty of practice material and the solutions so you can work on them, whenever you want.

Algebra Word Problem Solver

Free online algebra word problem solvers are a great way to learn how language is used to verbally represent algebra equations. Taking the help of a free online algebra word problem solver can help you translate them into correct equations. Word problem solvers for algebra break down the problem so that you understand the relation between the variables and form the right equation.

Solved Example

Question: One number is 5 more than another. The sum of  the smaller more than three times the larger, is 39.  What are the two numbers?

Solution:
Let x be the smaller number

Then the larger number is 5 more = x + 5

The problem states,

x + 3(x + 5) = 39
       
=> x + 3x + 15 = 39

=> 4x + 15 = 39

Subtract 15 from both sides of the equation,

=> 4x + 15 - 15 = 39 - 15

=> 4x = 24

Divide both side by 4,

=> $\frac{4x}{4} = \frac{24}{4}$

=> x = 6

=> x = $6$ is the smaller number.

So the larger number is x + 5 = 6 + 5 = $11$.