Algebra does not have a very good reputation among students. While some find it mildly frustrating, many are convinced that it is a form of modern day torture. So given all the bad press surrounding it, it is natural that first time algebra learners might be a bit apprehensive about what to expect. Well the good news is that algebra is not the killer subject that many claim it is. And even better, getting a hang of this subject early on makes the advanced levels easier and possibly even interesting! Algebra 1 problem solver is an online tool that will help you master algebra quite easily. With a math problem solver algebra 1 help is available easily any time you want. Algebra 1 problem solvers offer a lot of advantages.

Free Algebra 1 Problem Solver  

Algebra 1 equation solvers give you the extra help you need when you start a new subject. It explains any parts that you don’t understand and shows you examples so that you understand the solution thoroughly. Algebra 1 problem solver shows you the correct answers and the solution. The best thing about these online algebra 1 solvers is that they help you keep up with your lessons on a daily basis so that you don’t fall behind at all. Algebra 1 word problem solver define commonly used terms so that, with some practice, students are able to pick out information provided in the question quickly and accurately, and transcribe them into sentences. All free algebra 1 problem solvers have a database of practice problems that you can make use of and also have mock tests that test your improvement in the subject.

Solved Examples

Question 1: Solve the equation $\frac{2x}{ 3} + \frac{5}{7} = \frac{6x }{ 7}$ - 3

Solution:
Given $\frac{2x}{ 3} + \frac{5}{7} = \frac{6x }{ 7}$ - 3

Step 1:
The given equation has denominators that need to be cleared by multiplying all terms of the equation by the lowest common denominator.

LCD of the denominators 3 and 7 = 21

21($\frac{2x}{ 3} + \frac{5}{7}$) = 21($ \frac{6x }{ 7}$ - 3)

=> $\frac{2x * 21}{ 3} + \frac{5 * 21}{7}$ $ \frac{6x * 21}{ 7 }$ - 3 * 21

=> 7 * 2x + 3 * 5 = 3 * 6x - 21 * 3

=> 14x + 15 = 18x - 63

Step 2:
Solve for x,

=> 18x - 14x = 63 + 15

=> 4x = 78

Divide each side by 4

=> $\frac{4x}{4} = \frac{78}{4}$

=> x = 19 . 5 answer
 

Question 2: Factor the expression 10x2 + 20x - 80.

Solution:
Given 10x2 + 20x - 80

Given polynomial is quadratic polynomial
Solve for x,

Factorized the polynomial

=> 10x2 + 20x - 80 = 10x2 + 40x - 20x - 80

= 10x(x + 4) - 20(x + 4)

= (10x - 20)(x + 4)

=> 10x2 + 20x - 80 = (10x - 20)(x + 4). answer
 

Question 3: The sum of two numbers is 70. One number is six less than the other number. Find the smaller number.

Solution:
Let the two numbers be x and y.
also y is smaller than x (y < x).

Step 1:

Given sum of two numbers is 70

=> x + y = 70                             .......................................(1)

and one number is six less than the other number

=> y = x - 6                              .........................................(2)

Step 2: 
Solve equation (1) and equation (2)

Substitute equation (2) in (1)

=> x + (x - 6) = 70

=> x + x - 6 = 70

=> 2x - 6 = 70

Add 6 both sides

=> 2x - 6 + 6 = 70 + 6

=> 2x = 76

Divide each side by 2

=> $\frac{2x}{2} = \frac{76}{2}$

=> x = 38

Step 3: 
Put x = 38 in equation (2)

=> y = 38 - 6 

=> y = 32

Hence the smaller number is 32. answer