Solving equations would be much easier if someone would just explain them in plain English right? And of course explain the nuances of positive and negative signs traversing either side of the equal to sign. This is the kind of help that an online algebra equation solver offers. Online algebra equation solvers are the answer to many students who are discovering that algebra becomes much easier with clear simple explanations and regular practice. Accessed from the comfort of your home, everything you need to learn algebra is brought to you by free algebra equation solvers.

Algebra Equation Solver Free

Online algebra equation solvers cater to students in all grades, including college students. Algebra 1 equation solver covers the introductory topics in algebra like using rational numbers, algebra properties and rules. Algebra 2 equation solvers go a step further and introduce you to linear equations, quadratic equations, exponents and logarithms. Online tutorials which offer algebra equation solvers are like having your personal algebra helpers available whenever you need them with umpteen examples and step by step demonstrations. College algebra equation solvers cover advanced topics and are a real help when you are looking for more examples or varied practice worksheets. 

Solved Examples

Question 1: Solve for x, 13x + 45 = - 20

Solution:
Step 1:
Given, 13x + 45 = - 20

13x + 45 = - 20

Subtract 45 from each side

=> 13x + 45 - 45 = - 20 - 45

=> 13x = - 65

Step 2:

Divide each side by 13

=> $\frac{13x}{13} = \frac{- 65}{13}$

=> x = - 5.
 

Question 2: Solve log $\frac{xy^3}{z^2}$
Solution:
Given log $\frac{xy^3}{z^2}$

Step 1:

log $\frac{xy^3}{z^2}$

=> log xy3 - log z2

[log$\frac{m}{n}$ = log m - log n]

Step 2:

Again

log xy3 - log z2 = log x + log y3 - log z2

[log mn = log m + log n]


Step 3:


log x + log y3 - log z2  = log x + 3 log y - 2 log z

[log mn = n log m]

=> $\frac{xy^3}{z^2}$ = log x + 3 log y - 2 log z. answer
 

Step by Step Algebra Equation Solver

When you use algebra equation solver online help is available any time you need it. You have equation solvers at your disposal who can explain anything you need to know or clear any doubts. You also have the option of saving your work and returning to it later. Online algebra equation solver is a quick and convenient way to get the help you need.

Solved Examples

Question 1: Solve the quadratic equation by using formula
2x2 + 7x - 4 = 0
Solution:
Given quadratic equation, 2x2 + 7x - 4 = 0

Step 1:


2x2 + 7x - 4 = 0

Comparing with general quadratic equation

ax2 + bx + c = 0

a = 2, b = 7, c = - 4

Step 2:

b2 - 4ac = (7)- 4 * 2 * - 4

= 49 + 32

= 81

and

$\sqrt{b^2 - 4ac}$ = $\sqrt{81}$

= 9

=> $\sqrt{b^2 - 4ac}$ = 9

Step 3:

x = $\frac{- b \pm\sqrt{b^2 - 4ac}}{2a}$

=> x = $\frac{- 7 \pm9}{2*2}$

=> x = $\frac{- 7 + 9}{4}$   and    x = $\frac{- 7  - 9}{4}$

=> x = $\frac{2}{4}$    and    x = $\frac{- 16}{4}$

=> x = $\frac{1}{2}$      and    x = - 4

Hence the values of x are: $\frac{1}{2}$ , - 4. answer
 

Question 2: Find the value of p, 2x2 + p(2 - x) - 1 = 3, when x = 1.

Solution:
Step 1:
Given 2x2 + p(2 - x) - 1 = 3

2x2 + p(2 - x) - 1 = 3

=> 2x2 + 2p - px - 1 = 3

=> 2x2 + 2p - px  = 3 + 1

=> 2x2 + 2p - px  = 4

Step 2:

To find the value of p, put x = 1

=> 2 * 12 + 2p - p * 1 = 4

=> 2 * 1 + 2p - p = 4

=> 2 + p = 4

Subtract 2 from both sides

=> 2 + p - 2 = 4 - 2

=> p = 2

Answer: The value of p is 2.
 

Question 3: Solve $\frac{1}{m + 1} + \frac{2}{2m + 3}$
Solution:
Given, $\frac{1}{m + 1} + \frac{2}{2m + 3}$

Step 1
:
$\frac{1}{m + 1} + \frac{2}{2m + 3}$

LCM of the fractions = (m + 1)(2m + 3)

Step 2:


$\frac{1}{m + 1} + \frac{2}{2m + 3}$


= $\frac{2m + 3 + 2(m + 1)}{(m + 1)(2m + 3)}$

= $\frac{2m + 3 + 2m + 2}{(m + 1)(2m + 3)}$

= $\frac{4m + 5}{(m + 1)(2m + 3)}$

=> $\frac{1}{m + 1} + \frac{2}{2m + 3}$ = $\frac{4m + 5}{(m + 1)(2m + 3)}$